Thermodynamics – Quiz 18
Posted by Vishnu on August 21st, 2011 07:19 PM | No Comment
183. The area under the temperature-entropy curve (T-S curve) of any thermodynamic process represents
(a) work done during process
(b) heat absorbed only
(c) heat rejected only
(d) heat absorbed or rejected.
184. Choose the wrong statement
(a) The change of entropy is positive when ...
Thermodynamics – Quiz 17
Posted by Vishnu on August 21st, 2011 07:18 PM | No Comment
171. The law which states that change of internal energy of a perfect gas is directly proportional to the change of temperature, is known as
(a) Boyle's law . (b) Charle's law
(c) Joule's law (d) Avogadro's law.
172. The absolute zero pressure ...
Thermodynamics – Quiz 16
Posted by Vishnu on August 21st, 2011 07:17 PM | No Comment
161. A gas follows the law pVn=C. If the value of n— 1, the process is known as
(a) adiabatic (b) isothermal
(c)isentropic (d) polytropic.
162. For any thermodynamic process, the area under TS curve (temperature-entropy curve) represents
(a) work done by the system
(b) ...
Thermodynamics – Quiz 15
Posted by Vishnu on August 20th, 2011 08:56 PM | No Comment
149. Fig. 3.14 shows different air cycles on T-S diagrams. Fig. 3.14 (a) shows
(a) Otto cycle (b) Carnot cycle (c) Stirling cycle (d) Diesel cycle
150. Fig. 3.14 (a) shows
(a) Otto cycle (b) Carnot cycle (c) Stirling cycle (d) Diesel cycle
151. ...
Thermodynamics – Quiz 14
Posted by Vishnu on August 20th, 2011 08:54 PM | No Comment
140. At a temperature of 227°C the heat supplied to an engine is 250 kcal per second. Hleat rejection takes place at a constant temperature of 27°C. If heat rejected is 200 kcal/sec, then applying Clausius inequality, determine whether the ...
Thermodynamics – Quiz 13
Posted by Vishnu on August 20th, 2011 08:47 PM | No Comment
131. If cyclic ∫dQ/T >0, the cycle is
(c) irreversible
(d) none of the above.
(a) reversible (b) impossible
132. A heat engine is supplied with 300 kcal/sec of heat at constant fixed temperature of 250° G. If 200 kcal/sec are rejected at 10°C, ...
Thermodynamics – Quiz 12
Posted by Vishnu on August 20th, 2011 08:45 PM | No Comment
121. In case of hyperbolic expansion of a gas, the work done is equal to
(b) p1V1logeV2/V1
(a) p1V1loge(V1+V2)/V2
(c) (p1V1-p 2V2)
(d) p1V1logeV1/V2
where V1 — volume of gas before expression and V2—volume after expansion.
122. In case of hyperbolic expansion of a gas, heat ...